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webman api 出現(xiàn)404或者全局報(bào)錯(cuò)怎么以json格式返回

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1個(gè)回答
weijer

support/exception/Handler.php

 public function render(Request $request, Throwable $exception): Response
    {
        return new Response(200, ['Content-Type' => 'application/json'], $exception->getMessage());
    }

我是定義了一個(gè) HttpResponseException.php , 然后封裝了異常拋出函數(shù)

<?php

namespace support\exception;

class HttpResponseException extends \Exception
{}

support/exception/Handler.php

       if ($exception instanceof HttpResponseException) {
            // 拋出運(yùn)行時(shí)異常
            return new Response(200, ['Content-Type' => 'application/json'], $exception->getMessage());
        }
        return parent::render($request, $exception);
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